Question

Determine the final temperature of a 25.0 g block of metal that absorbs 255 cal of energy. The initial temperature of the block was 17.0 C. The specific heat capacity of the metal is 2.72 J/g.C.

Answer 1

To determine the specific heat capacity of the metal, we use the formula Q = mcΔT and plug in the given values. The specific heat capacity is approximately 0.476 J/g°C. To predict the metal's identity, we can compare its specific heat capacity to known values.

Step-by-step explanation:

To determine the specific heat capacity of a metal, we can use the formula Q = mcΔT, where Q is the heat absorbed, m is the mass of the metal, c is the specific heat capacity, and ΔT is the change in temperature. In this case, the metal absorbs 1.43 kJ of heat, so we convert this to joules (1 kJ = 1000 J) and plug in the given values:

Q = 1.43 kJ x 1000 J/kJ = 1430 J

m = 217 g

ΔT = 39.1 °C - 24.5 °C = 14.6 °C

Now, we can rearrange the formula to solve for c:

c = Q / (m x ΔT) = 1430 J / (217 g x 14.6 °C) ≈ 0.476 J/g°C

Therefore, the specific heat capacity of the metal is 0.476 J/g°C. To predict its identity, we can compare this value to known specific heat capacities of different metals.