Question

After executing the code: int numbers[3] = {1,2,3}; int *ptr; ptr = numbers+1;, what will be the value of *ptr?

A) 1
B) 2
C) 3
D) Undefined

Answer 1

The value of *ptr after executing the provided code will be 2, since *ptr dereferences the second element of the array numbers.

Step-by-step explanation:

When you execute the code int numbers[3] = {1,2,3}; int *ptr; ptr = numbers+1;, you are initializing an array with the values 1, 2, and 3 and then creating a pointer that points to the second element of that array. This is because ptr is set to point to numbers, which is the address of the first element of the array, and then you're adding 1 to that address, thus making ptr point to the second element of the array. Thus, the value of *ptr will be 2, because *ptr dereferences the pointer ptr, which is pointing to the second element of the numbers array.