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A device with a resistance of 200.0kΩ connected to a 10.0v Battery. How much power does the device use?

a. 2,000kW
b. 20,000kW
c. 0.050mW
d. 0.50mW

1 Answer

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Final answer:

The power used by a device with a resistance of 200.0kΩ when connected to a 10.0V battery is calculated using the formula P = V^2 / R, yielding 0.5mW of power.

Step-by-step explanation:

The question asks for the power used by a device with a resistance of 200.0kΩ when connected to a 10.0V battery. To find the power, we can use the formula for power dissipation in a resistor, which is P = V2 / R, where P is the power in watts, V is the voltage in volts, and R is the resistance in ohms.

First, we should convert the resistance from kilohms to ohms: 200.0kΩ = 200,000Ω. Using the formula, we get:

P = 10.0V2 / 200,000Ω = 0.0005W or 0.5mW.

Therefore, the device uses 0.5mW of power when connected to a 10.0V battery, which corresponds to option (d).

User John Fear
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