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Complete the point-slope equation of the line through (-2,6) and (1,1)

y-6=

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The point-slope equation of the line passing through (-2, 6) and (1, 1) is y - 6 = (-5/3)(x + 2).

To find the point-slope equation of the line passing through the points (-2, 6) and (1, 1), we can use the formula:

y - y₁ = m(x - x₁),

where (x₁, y₁) represents the coordinates of one point on the line, and m represents the slope of the line.

First, let's find the slope (m) using the formula:

m = (y₂ - y₁) / (x₂ - x₁),

where (x₁, y₁) = (-2, 6) and (x₂, y₂) = (1, 1):

m = (1 - 6) / (1 - (-2))

= -5 / 3.

Now, we can substitute the values of (x₁, y₁) = (-2, 6), m = -5/3 into the point-slope equation:

y - 6 = (-5/3)(x - (-2)).

Simplifying further:

y - 6 = (-5/3)(x + 2).

Therefore, the point-slope equation of the line passing through (-2, 6) and (1, 1) is y - 6 = (-5/3)(x + 2).

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