Question

A 0.150 kg baseball traveling with a horizontal speed of 4 m s' is hit by a bat and then moves with a speed of 35 m s' in the opposite direction. What is the force of the baseball bat on the ball causing this to happen if the bat is in contact with the ball for 0.2 seconds?

Answer 1

The force of the baseball bat on the ball is 10.7 Newtons in the opposite direction.

Step-by-step explanation:

The force of the baseball bat on the ball can be calculated using Newton's second law of motion, which states that force is equal to the change in momentum divided by the time interval. Momentum is the product of mass and velocity. In this case, the mass of the baseball is 0.150 kg and the change in velocity is from -4 m/s to 35 m/s. The time interval is given as 0.2 seconds. The formula to calculate force is:

Force = (m * Δv) / t

where m is the mass, Δv is the change in velocity, and t is the time interval.

Substituting the given values:

Force = (0.150 kg * (35 m/s - (-4 m/s))) / 0.2 s

Simplifying the equation:

Force = 10.7 N

Therefore, the force of the baseball bat on the ball is 10.7 Newtons in the opposite direction.