Answer:
it loses 3 electrons from 3s and 3p orbitals and attains the noble gas configuration of Neon.
Step-by-step explanation:
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3 electrons
aluminum : [Ne]3s23p1 [ N e ] 3 s 2 3 p 1 . It loses 3 electrons from 3s and 3p orbitals and attains the noble gas configuration of Neon.
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