Question

How much 75% alcohol must be mixed with 20% alcohol to make 1 pint of a 40% alcohol?

a. 87 ml of 75% alcohol and 153 ml of 20%
b. 172 ml of 75% and 301 ml of 20%
c. 182 ml of 75% and 318 ml of 20%
d. 364 ml of 75% and 636 ml of 20%

Answer 1

To solve this problem, set up an equation to represent the amount of alcohol in each solution and solve for the values of x and y. The correct answer is option c: 182 mL of 75% alcohol and 318 mL of 20% alcohol.

Step-by-step explanation:

To solve this problem, we can set up an equation based on the amount of alcohol in each solution. Let x represent the amount of 75% alcohol that needs to be mixed, and let y represent the amount of 20% alcohol. The equation can be written as:

0.75x + 0.20y = 0.40 * 1 pint

Since we are dealing with a pint, we can convert it to milliliters by multiplying by 473.18 (1 pint = 473.18 mL).

Next, we can solve the equation to find the values of x and y. The correct answer is option c: 182 mL of 75% alcohol and 318 mL of 20% alcohol.