Question

A man heterozygous for big ears reproduces with a woman who is homozygous recessive for small ears. What are the chances that they will have a child who is homozygous dominant for big ears?

A) 0%
B) 25%
C) 50%
D) 75%

Answer 1

Given that the father is heterozygous for big ears (Bb) and the mother is homozygous recessive for small ears (bb), their children have a 0% chance of being homozygous dominant for big ears (BB).

Step-by-step explanation:

The question relates to genetics and the probability of offspring inheriting particular genotypes based on the parental genes. A man who is heterozygous for big ears (let's denote the big ears allele as 'B' and the small ears allele as 'b') has the genotype Bb. The woman is homozygous recessive for small ears, which means her genotype is bb. When you draw out a Punnett square to determine the potential genotypes of their offspring, each child has a 0% chance of being homozygous dominant for big ears (BB), since the mother does not carry the 'B' allele. The possible genotypes from this pair are: 50% chance (Bb) of being heterozygous with big ears and a 50% chance (bb) of being homozygous recessive with small ears.