Question

If a woman has the genotype of AaBB, what are her four possible gametes that she can produce?

A) AB, Ab, aB, ab
B) ABB, ABB, ABB, ABB
C) AB, aB, ABB, Abb
D) Aa, BB, Aa, BB

Answer 1

A woman with genotype AaBB can produce four types of gametes: AB, Ab, aB, and ab, aligning with Mendel's law of independent assortment.

Step-by-step explanation:

If a woman has the genotype of AaBB, the four possible gametes that she can produce are AB, Ab, aB, and ab. This is in accordance with Mendel's law of independent assortment, which states that alleles for different traits are distributed to sex cells (&gametes) independently of one another. This means that each gamete will have one allele from each gene. Since the 'Aa' genotype exhibits two different alleles (A and a) and the 'BB' genotype has two of the same alleles (B and B), the gametes will be combinations of these alleles. However, as 'BB' is homozygous, it will only contribute a B to each gamete. Thus the woman can produce gametes that are AB, with an A allele from the 'Aa' gene pair and a B allele from the 'BB' gene pair, as well as gametes that are aB, with an a allele from the 'Aa' gene pair and a B allele from the 'BB' gene pair.