Question

Bird is fiying directly toward a stationary bird-watcher and emits a frequency of

1200 Hz. The bird-watcher, however, hears a frequency of 1240 Hz. What is the speed of the bird? [The speed of sound in air is 343 m/s]
• 18.4 m/s
• 15.6 m/s
• 14.3 m/s
• 23.7 m/s
• 11.1 m/s

Answer 1

The speed of the bird is 14.3 m/s

Step-by-step explanation:

The bird is flying directly toward the stationary bird-watcher.

To determine the speed of the bird, we can use the Doppler effect equation, which relates the observed frequency to the actual frequency and the relative velocity:

(Observed frequency) = (Actual frequency) x ((Speed of sound + Speed of the bird) / Speed of sound)

In this case, the observed frequency is 1240 Hz and the actual frequency is 1200 Hz. The speed of sound in air is given as 343 m/s. Plugging in these values, we can solve for the speed of the bird:

1240 Hz = 1200 Hz x ((343 m/s + Speed of the bird) / 343 m/s)

Simplifying this equation will give us the speed of the bird as 14.3 m/s.