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1 loop in the primary coil and 8 loops in the secondary. If the secondary voltage is 120 V, what must be the primary voltage

1 Answer

8 votes

Answer:


V_(p) = 15 V

Step-by-step explanation:

Given the following data;

Number of loops in primary coil, Np = 1 loop.

Number of loops in secondary coil, Ns = 8 loops

Voltage in secondary coil, Vs = 120V

To find the voltage in the primary coil, Vp;

Transformer ratio is given by the formula;


(V_(p))/(V_(s)) = (N_(p))/(N_(s))

Making Vp the subject of formula;


V_(p) = (N_(p))/(N_(s)) * V_(s)

Substituting into the equation, we have;


V_(p) = (1)/(8) * 120


V_(p) = (120)/(8)


V_(p) = 15 V

Therefore, the voltage in the primary coil, Vp is 15 Volts.

User Minesh
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