Question

How many grams of C6H6 liquid must decompose according to the following chemical equation to transfer 430 kJ of heat? C₆H₆_(l)--> 3_C₂H₂(a) ?H=630kJ

Answer 1

To transfer 430 kJ of heat, 53.284 grams of C6H6 liquid must decompose according to the chemical equation C₆H₆(l) → 3C₂H₂(g).

Step-by-step explanation:

To determine how many grams of C6H6 liquid must decompose to transfer 430 kJ of heat, we need to use the enthalpy change (ΔH) from the balanced chemical equation and the molar mass of C6H6. The given chemical equation is C₆H₆(l) → 3C₂H₂(g), and the enthalpy change (ΔH) is 630 kJ. We can use the molar mass of C6H6 (78.11 g/mol) and the stoichiometry of the equation to find the amount in moles. Finally, we can convert the moles of C6H6 to grams using its molar mass.

Let's go through the calculations step by step:

1. Convert the given heat transfer from kJ to J: 430 kJ × 1000 J/kJ = 430,000 J
2. Calculate the moles of C6H6 that decompose: ΔH/ΔH of the given reaction = 430,000 J/630,000 J/mol = 0.6825 mol C6H6
3. Convert moles of C6H6 to grams using its molar mass: 0.6825 mol × 78.11 g/mol = 53.284 g

Therefore, 53.284 grams of C6H6 liquid must decompose to transfer 430 kJ of heat.