Question

What is the identity of a 100. g sample of metal that, upon absorbing 4680 J of heat, increases in temperature by 52.0°C?

A) Mg
B) Al
C) Ti
D) Fe

Answer 1

To determine the identity of the metal, we need to calculate its specific heat. Using the given values and the formula for specific heat, we find the specific heat of the metal to be 21.7 J/g·°C. Comparing this value to the specific heat values of known metals, we determine that the metal is Aluminum (Al).

Step-by-step explanation:

To determine the identity of the metal, we need to calculate its specific heat.

The formula for specific heat is:

q = m * c * ΔT

Where q is the heat absorbed, m is the mass of the metal, c is the specific heat, and ΔT is the change in temperature.

Using the given values, we can rearrange the formula to solve for c:

c = q / (m * ΔT)

Plugging in the values, we get:

c = (1.43 kJ * 1000 J/kJ) / (217 g * (39.1 °C - 24.5 °C))

c = 21.7 J/g·°C

Now, we can compare the specific heat of the metal to the specific heat values of known metals.

The metal with the closest specific heat value is Aluminum (Al), which has a specific heat of 24.0 J/g·°C.

Therefore, the identity of the metal is Aluminum (Al).