Question

How many moles of KClO₃ solid must be reacted according to the following balanced chemical equation to transfer -34.2kJ of heat? 2KClO₃(s)--> 2KCl(s)+3_O₂(g) ?H=-89.4

Answer 1

The number of moles of KClO₃ solid that must be reacted to transfer -34.2 kJ of heat according to the balanced chemical equation is 0.38 mol.

Step-by-step explanation:

The enthalpy change for the given balanced chemical equation is -89.4 kJ.

We can use the formula q = m*C*ΔT, where q is the heat transferred, m is the mass of the substance, C is the specific heat capacity, and ΔT is the change in temperature.

Since we have ΔH (enthalpy change) and we want to find the number of moles of KClO₃, we can use the equation ΔH = nΔH (enthalpy change) to solve for n (number of moles of KClO₃). Rearranging the equation, we have n = ΔH / ΔH. Plugging in the given values, we get n = (-34.2 kJ) / (-89.4 kJ/mol KClO₃) = 0.38 mol KClO₃.