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Tickets for a raffle cost $18. There were 823 tickets sold. One ticket will be randomly selected as the winner, and that person wins $1400 and also the person is given back the cost of the ticket. For someone who buys a ticket, what is the expected value (the mean of the distribution

Tickets for a raffle cost $18. There were 823 tickets sold. One ticket will be randomly-example-1
User Dstromberg
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Final answer:

The expected value of buying a raffle ticket in this scenario is approximately -$16.27, which means on average, a person expects to lose $16.27 per ticket purchased.

Step-by-step explanation:

To find the expected value for someone who buys a raffle ticket, we need to calculate the mean of the distribution of possible outcomes for a ticket purchase. In this scenario, a ticket costs $18, and the total number of tickets sold is 823. The winner receives $1400 plus the cost of their ticket, which is $18, so the total prize is $1418. The probability of winning the prize is 1/823, as there is only one winner.

The probability of not winning is 822/823. Therefore, the expected value (E) for a ticket can be calculated using the formula:

E = (Probability of winning × Winnings) + (Probability of not winning × Loss)

The loss is the cost of the ticket ($18) since you do not receive any prize if you do not win. So the calculation is:

E = (1/823) × $1418 + (822/823) × (-$18)

Now, we perform the multiplication:

  • (1/823) × $1418 = $1.72 approximately
  • (822/823) × (-$18) = -$17.99 approximately

Adding these together gives us the expected value:

E = $1.72 - $17.99

= -$16.2

Therefore, the expected value for a person buying a ticket is approximately -$16.27, which means on average, a person expects to lose $16.27 per ticket purchased.

User Jan Kyu Peblik
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