Question

Write an equation of the parabola that has the same shape as the graph of f(x)=2x^2​, but with (6,9) as the vertex.

Answer 1

`f(x)=2(x-6)^2+9`

Explanation:

As
`f(x)=2x^2` has vertex (0,0) we need to move the function 6 units on the x-axes and 9 units on the y-axes, and it is done by substracting 6 to the x variable and adding 9 to the resulting function after the first movement