Final answer:
The tables are used to find the molecular mass of chloroform and a benzene derivative by multiplying the quantity of each element by its atomic mass and summing the results, illustrating a common practice in chemistry.
Step-by-step explanation:
The two scenarios described are exercises in calculating the molecular mass of molecules using a data table that includes the elemental composition, quantity of each element, and the average atomic mass (amu) of each element. In both tables, by performing multiplication of the quantity of each element by its corresponding atomic mass and summing the subtotals, one can determine the molecular mass of the molecule represented in each diagram.
In the first scenario, the molecule appears to be chloroform (CHCl3), as indicated by the molecular diagram with one carbon (C), one hydrogen (H), and three chlorine (Cl) atoms. The molecular mass is calculated and presented in the merged cell at the bottom of the first five columns of the table, aligning with the instructional theme of merging cells as stated in the initial question.
In the second scenario, the molecule seems to be a derivative of benzene or a related aromatic compound based on the ring structure and attached groups, indicated by the symbols C for carbon, H for hydrogen, and O for oxygen. Similar to the first scenario, the molecular mass is shown in the merged cell at the bottom of the first five columns.