234k views
5 votes
What is the quotient of the complex number 4-3i divided by its conjugate?

User Moorepants
by
3.5k points

1 Answer

7 votes

9514 1404 393

Answer:

0.28 -0.95i

Explanation:

Multiply numerator and denominator by the conjugate of the denominator.


(4-3i)/(4+3i)=((4-3i)(4-3i))/((4+3i)(4-3i))=(7-24i)/(25)=\boxed{0.28-0.96i}

_____

Additional comment

If the original number is A∠β, the ratio is 1∠(2β), the square of the unit vector in the same direction as the original.

User Wasilikoslow
by
4.5k points