Question

What does the umpire call when the player dribbles/bounces the ball?

a) Dribble violation.
b) Bounce infringement.
c) Play on.
d) Footwork penalty.

Answer 1

In basketball, if the dribbling is legal, the umpire will call 'Play on.' To reach a height of 1.25 m above the floor, a player needs to calculate the initial velocity using the equation v = √(2gh), where 'g' is the acceleration due to gravity and 'h' is the desired height.

Step-by-step explanation:

When a basketball player dribbles or bounces the ball during a game, the umpire does not typically make a specific call if the dribbling is done according to the rules. If the dribbling is legal, the correct call would be c) Play on. However, if there is a violation, such as a double dribble or carrying the ball, a different call would be made.

In terms of the physics question: To determine the initial velocity necessary for a basketball player to leave the ground and rise to a height of 1.25 m, the equation derived from kinematic principles can be used. This equation combines the acceleration due to gravity and the maximum height the player needs to reach. Using the equation v = √(2gh), where v is the initial velocity, g is the acceleration due to gravity (approximately 9.81 m/s2), and h is the height (1.25 m), the required initial velocity can be calculated.

Answer 2

A basketball player must achieve an initial velocity of approximately 4.95 m/s to leap 1.25 meters high during the starting tip-off in basketball.

Step-by-step explanation:

When answering the question of what velocity a basketball player must leave the ground to rise 1.25 m above the floor to attempt to get the ball at a tip-off, we turn to physics and specifically the principles of kinematics. Using the equation for vertical motion:

Vf^2 = Vi^2 + 2ad,

where Vf is the final velocity (0 m/s at the peak of the jump), Vi is the initial velocity, a is the acceleration due to gravity (approximately -9.81 m/s^2), and d is the distance (1.25 m in this case).

By rearranging the formula to solve for Vi, the initial velocity needed to reach the height of 1.25 m, the calculation would be:

Vi = √(-2 * gravity * height),

which gives us:

Vi = √(-2 * -9.81 m/s^2 * 1.25 m) = √(24.525) = approximately 4.95 m/s.

This is the velocity at which a basketball player must dribble/bounce the ball to leave the ground to reach a height of 1.25 meters.