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What is the molecular weight of 783 g of lead(II) nitrite? Answer in units of g/mol

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Final answer:

The molecular weight of lead(II) nitrite (Pb(NO3)2) is 331.2 g/mol.

Step-by-step explanation:

To find the molecular weight of lead(II) nitrite, we need to calculate the total number of grams in 1 mole of the compound. The molecular formula of lead(II) nitrite is Pb(NO3)2, where the atomic weights of Pb, N, and O are 207.2 g/mol, 14.0 g/mol, and 16.0 g/mol, respectively.

The molecular weight of Pb(NO3)2 can be calculated as follows:

  • 1 mole of Pb weighs 207.2 g
  • 2 moles of N weighs 2 * 14.0 = 28.0 g
  • 6 moles of O weighs 6 * 16.0 = 96.0 g

Therefore, the molecular weight of Pb(NO3)2 is 207.2 g + 28.0 g + 96.0 g = 331.2 g/mol.

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