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Consider the following expression that compiles: methodA(x,y) && !methodB(x) What type does methodB return?

Select one:
a. int
b. Any numeric type
c. the same as the type of x
d. String
e. Could be any type as long as it's the same as the type returned by methodA()
f. boolean

1 Answer

4 votes

Final answer:

In the expression 'methodA(x,y) && !methodB(x)', the methodB must return a boolean type to work with the logical NOT and AND operators.

Step-by-step explanation:

The expression methodA(x,y) && !methodB(x) utilizes the logical AND operator (&&) and the logical NOT operator (!). For the expression to compile and evaluate correctly in many programming languages, methodB must return a boolean type. This is because the NOT operator is applied to the result of methodB(x), and can only be applied to boolean values. The result of methodB(x) is then combined with the result of methodA(x,y) using the AND operator, which also operates on boolean values. Thus, the correct answer is f. boolean.

User Kun Ling
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