Question

What is the output of the following piece of code? ____________________ int x = 4, y = 3; boolean b = ++x < y++ || ++x < y++; System.out.println(x+","+y+","+b); ____________________ Select one:

a. 4,3,false
b. 5,4,false
c. 5,6,false
d. 4,3,true
e. 5,4,true
f. 6,5,false

Answer 1

The code increments x twice and y once, resulting in these values.

e. 5,4,true int x = 4, y = 3; boolean b = ++x < y++ || ++x < y++; System.out.println(x+","+y+","+b); e. 5,4,true Select one.

Step-by-step explanation:

In the given code, there are two variables, `x` and `y`, initialized to 4 and 3, respectively. The boolean variable `b` is assigned the result of the logical OR operation between two expressions involving pre-increment and post-increment of `x` and `y`. Let's break down the evaluation step by step.

1. ++x &lt; y++:Pre-increment `x` (now x=5) is compared with the current value of `y` (y=3) before its post-increment. This condition is true, as 5 is less than 3.

2. ++x &lt; y++: Again, pre-increment `x` (now x=6) is compared with the current value of post-incremented `y` (y=4). This condition is also true, as 6 is less than 4.

3. Result of OR Operation: Since the logical OR operator (||) returns true if at least one condition is true, the final value of `b` is true.

4. Print Statement: The `System.out.println(x+","+y+","+b)` statement then prints the values of `x`, `y`, and `b`, resulting in "5,4,true".

In summary, the code increments `x` twice and `y` once, leading to the final values of `x=5`, `y=4`, and `b=true`. Therefore, the correct answer is option e: 5,4,true.