Final answer:
The 'out' modifier indicates that a parameter is passed by reference to a method and will be assigned a value by that method, which can be used after the method execution.
Step-by-step explanation:
The "out" modifier in programming languages like C# denotes that a parameter is passed by reference but is only intended to be written to by the method. Essentially, using the out modifier indicates that the method will output a value through that parameter. Unlike the "ref" modifier, variables passed as out arguments do not need to be initialized before being passed to the method, because the method is expected to assign a value before it returns. For example, the method signature void ExampleMethod(out int result) shows that ExampleMethod will provide a value for result that the caller can then use after the method execution is completed.