Final answer:
The angular velocity, torque, change in angular momentum, and tangential acceleration of a mass on the end of a rod can be calculated using basic physics formulas involving the radius, applied force, time, and mass.
Step-by-step explanation:
The student's question is about calculating the angular velocity, torque, and change in angular momentum of a mass attached to a rod after one minute and its tangential acceleration.
To calculate the angular velocity, we assume that there is an initial angular acceleration caused by the torque due to the force. To find the angular acceleration, α, we can use Newton's second law for rotation, which states α = τ / I, where τ is the torque and I is the moment of inertia. The torque can be calculated using τ = r × F, where r is the distance from the pivot point to the point where the force is applied and F is the force. In this case, τ = 0.75 m x 15 N = 11.25 N·m. The moment of inertia, I, for a point mass is I = m × r^2, which for a 100 g mass is I = 0.1 kg × (0.75 m)^2.
Once we have α, we can calculate the angular velocity, ω, using ω = ω_0 + α × t, where ω_0 is the initial angular velocity (which we assume to be 0), and t is the time. After one minute (60 seconds), ω will be α × 60 seconds.
The change in angular momentum, ΔL, can be calculated using ΔL = I × Δω, where Δω is the change in angular velocity, which is simply ω since the initial velocity is 0.
The tangential acceleration, a_t, can be found using a_t = r × α.