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16 votes
A speedboat increases its speed from 13.5 m/s to 27.4 m/s in a distance of 241 m. Determine the time over which this acceleration occurs?

User NOZUONOHIGH
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1 Answer

16 votes
16 votes

V² = U² + 2aS

27.4² = 13.5² + 2*241a

750.76 = 182.25 + 482a

750.76 - 182.25 = 482a

568.51/482

a = 1.18m/s^2

User Kedar B
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