Final answer:
To calculate q in Joules for cooling 6.6 g of ice from -21.4°C to -97.8°C, multiply the mass of the ice by its specific heat capacity and the change in temperature, resulting in -1049.5016 J, which indicates heat removal.
Step-by-step explanation:
To calculate q in Joules when 6.6 g of ice is cooled from -21.4°C to -97.8°C, we use the specific heat capacity formula:
q = m × c × ΔT,
where m is the mass of the ice, c is the specific heat capacity of ice, and ΔT is the change in temperature.
Here, m = 6.6 g, c = 2.087 J/g·K, and ΔT = (-97.8°C) - (-21.4°C) = -76.4 K.
Therefore, q = 6.6 g × 2.087 J/g·K × -76.4 K = -1049.5016 J,
Since heat is being removed, q is negative, indicating an exothermic process. For the purpose of this answer, we are interested in the magnitude of heat transfer, which is 1049.5016 J (rounded to 1049.5 J if required).