Question

How much heat flows (in J) when a 29.0 gram block of metal changes temperature from 15 °C to 72 °C? The specific heat of the metal is 0.424 J/g°C.

a) 700
b) -24
c) -3900
d) -1700
e) -700

Answer 1

The amount of heat flow when a 29.0 gram block of metal changes temperature from 15 °C to 72 °C with a specific heat of 0.424 J/g°C is approximately 700 J, making option a) the correct choice.

Step-by-step explanation:

The amount of heat that flows when the temperature of a substance changes can be calculated using the formula Q = mcΔT, where Q is the heat flow in joules, m is the mass in grams, c is the specific heat capacity in J/g°C, and ΔT is the change in temperature in degrees Celsius. For the given problem, we have a 29.0 gram block of metal with a specific heat of 0.424 J/g°C. The temperature change is from 15 °C to 72 °C. Thus, the change in temperature (ΔT) is 72 °C - 15 °C = 57 °C.

Using the formula:
Q = (29.0 g)(0.424 J/g°C)(57 °C)
Q = 699.192 J
The heat flow is approximately 700 J, so the closest option is a) 700.