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A 2.74 kg block initially at rest is pulled to the right along a horizontal surface by a constant horizontal force of 17.8 n. the coefficient of kinetic friction is 0.137 m/s². the acceleration of gravity is 9.8 m/s². find the speed of the block after it has moved 4.34 m.

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Final answer:

To find the speed of the block after moving a certain distance on a horizontal surface with an applied force and known kinetic friction, apply Newton's second law to calculate the net force and use kinematic equations to determine final velocity.

Step-by-step explanation:

The student asks a question related to kinematics and friction, which is a part of Physics. To determine the speed of the block after it has moved a certain distance with a given coefficient of kinetic friction, we need to apply Newton's second law of motion and kinematic equations. The net force acting on the block can be calculated by subtracting the frictional force from the applied force. The frictional force, Ff, is the product of the coefficient of kinetic friction and the normal force. With the net force known, we can find the acceleration using the equation a = Fnet/m. Finally, using the kinematic equation v2 = u2 + 2as, where u = 0 m/s (initial velocity), a is the acceleration, and s is the distance, we can determine the final velocity v of the block.

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