Final answer:
The period of a mass oscillating on a horizontal spring with a frequency of 3.40 Hz is calculated as the reciprocal of the frequency and is approximately 0.2941 seconds.
Step-by-step explanation:
To determine the period of an oscillating mass attached to a spring with a given frequency, we can use the relationship between period (T) and frequency (f), which is T = 1/f. The student has provided that the frequency of oscillation is 3.40 Hz. Therefore, the period T is the reciprocal of the frequency.
Performing the calculation:
- T = 1/f
- T = 1/3.40 Hz
- T = 0.2941 seconds (rounded to four decimal places)
The period of the mass-spring system is approximately 0.2941 seconds.