Final answer:
The mass of 0.40 mol of dimethylnitrosamine is calculated by multiplying the number of moles (0.40 mol) by its molar mass (115.13 g/mol), which equals 46.052 g.
Step-by-step explanation:
The mass of 0.40 mol of dimethylnitrosamine is a calculation using the molar mass of the compound (CH₃)₂N₂O. To find this mass, we start by determining the molar mass of dimethylnitrosamine, which sums the atomic masses of all atoms present in the formula:
- Carbon (C): 12.01 g/mol x 6 = 72.06 g/mol
- Hydrogen (H): 1.01 g/mol x 12 = 12.12 g/mol
- Nitrogen (N): 14.01 g/mol x 2 = 28.02 g/mol
- Oxygen (O): 16.00 g/mol x 1 = 16.00 g/mol
Adding these up, we find that the molar mass of dimethylnitrosamine is approximately 115.13 g/mol. Now, using the formula:
Mass = Number of moles × Molar mass
Mass = 0.40 mol × 115.13 g/mol = 46.052 g
Therefore, the mass of 0.40 mol dimethylnitrosamine is 46.052 g.