The optimal solution is to schedule 75 days at location I and 54 days at location II, resulting in a minimum cost of $89,550 to fulfill the drapery orders.
Certainly! Let's go through the calculations step by step:
a. Linear Programming Model:
The objective function is Z = 600x1 + 825x2, and the constraints are:
10x1 + 20x2 ≥ 2000 (Deluxe drapes)
20x1 + 50x2 ≥ 4200 (Better drapes)
13x1 + 6x2 ≥ 1200 (Standard drapes)
x1, x2 ≥ 0 (Non-negativity)
b. Corner Point Method:
To find the corner points, solve the systems of equations formed by pairs of constraints. The corner points are the intersections.
Corner Point 1:
Solve:
10x1 + 20x2 = 2000
20x1 + 50x2 = 4200
Solving, we get x1 = 120 and x2 = 76.
Corner Point 2:
Solve:
20x1 + 50x2 = 4200
13x1 + 6x2 = 1200
Solving, we get x1 = 75 and x2 = 54.
Corner Point 3:
Solve:
10x1 + 20x2 = 2000
13x1 + 6x2 = 1200
Solving, we get x1 = 60 and x2 = 70.
c. Minimum Cost:
Evaluate Z = 600x1 + 825x2 at each corner point:
For Corner Point 1: Z = 600(120) + 825(76) = 115,200 + 62,700 = 177,900
For Corner Point 2: Z = 600(75) + 825(54) = 45,000 + 44,550 = 89,550
For Corner Point 3: Z = 600(60) + 825(70) = 36,000 + 57,750 = 93,750
The minimum cost occurs at Corner Point 2, where x1 = 75 and x2 = 54, with a minimum cost of $89,550