Answer:
-4.84
Step-by-step explanation:
To determine how long it will take for the rocket to hit the ground, we need to find the time at which the height of the rocket, represented by the function h(t) = 16t² + 92t + 24, equals zero.
Setting h(t) equal to zero, we have:
16t² + 92t + 24 = 0
To solve this quadratic equation, we can use the quadratic formula:
t = (-b ± √(b² - 4ac)) / (2a)
In this case, a = 16, b = 92, and c = 24. Plugging these values into the quadratic formula, we get:
t = (-92 ± √(92² - 4 * 16 * 24)) / (2 * 16)
Simplifying further:
t = (-92 ± √(8464 - 1536)) / 32
t = (-92 ± √6928) / 32
Calculating the square root of 6928, we get:
t = (-92 ± 83.24) / 32
Now, we have two possible solutions:
t₁ = (-92 + 83.24) / 32
-0.27
t₂ = (-92 - 83.24) / 32
-4.84
Since time cannot be negative in this context, we discard the negative solution. Therefore, the rocket will hit the ground approximately 4.84 seconds after it was launched.
Please note that the provided answer is an approximation and may vary slightly depending on the level of precision required.