Final answer:
The heat released when 16.2 g of liquid mercury at 25°C is cooled to a lower reference temperature is calculated using the specific heat capacity of mercury and the mass and temperature change. It amounts to 56.7 joules.
Step-by-step explanation:
The heat released when 16.2 g of liquid mercury at 25°C can be calculated using the formula q = mcΔT, where q is the heat released in joules (J), m is the mass in grams (g), c is the specific heat capacity in J/g°C, and ΔT is the change in temperature in degrees Celsius (°C). The specific heat capacity of mercury is approximately 0.14 J/g°C. To calculate the heat released:
q = (16.2 g)(0.14 J/g°C)(25°C) = 56.7 J.
Therefore, the heat released is 56.7 J when 16.2 g of liquid mercury is cooled from 25°C to some lower reference temperature, such as the temperature of the surroundings.
The heat released when 16.2 g of liquid mercury at 25°C is 56.7 J.
To calculate the heat released when 16.2 g of liquid mercury at 25°C, we need to use the specific heat capacity of mercury and the equation: q = mcΔT where q is the heat released, m is the mass of mercury, c is the specific heat capacity of mercury, and ΔT is the change in temperature. The specific heat capacity of mercury is 0.14 J/g°C. Plugging in the values: q = (16.2 g)(0.14 J/g°C)(25°C) = 56.7 J. Therefore, the heat released when 16.2 g of liquid mercury at 25°C is 56.7 J.