Question

An arrow is shot straight up with an initial speed of 98 m/s. nine seconds later its speed straight up is only 9.8 m/s. at what rate is the arrow accelerated by the pull of the earth’s gravitational field?

Answer 1

The arrow is accelerated downwards by the pull of the Earth's gravitational field at a rate of 9.8 m/s^2.

Step-by-step explanation:

The rate at which an object accelerates due to the pull of the Earth's gravitational field is represented by the acceleration due to gravity. In this case, the arrow is shot straight up with an initial speed of 98 m/s and nine seconds later its speed is 9.8 m/s. We can use the kinematic equation v = u + at to find the acceleration, where v is the final velocity, u is the initial velocity, and t is the time taken. Plugging in the values, we get:

9.8 = 98 + a * 9

Simplifying the equation, we get:

a = (9.8 - 98)/9 = -9.8 m/s^2

Therefore, the arrow is accelerated downwards by the pull of the Earth's gravitational field at a rate of 9.8 m/s^2.