Question

You are helping with some repairs at home. You drop a hammer and it hits the floor at a speed of 8 feet per second. If the acceleration due to gravity (g) is 32 feet/second², how far above the ground (h) was the hammer when you dropped it? Use the formula: v=sqrt(2gh)

A. 1.0 foot
B. 8.0 feet
C. 16.0 feet
D. 2.0 feet

Answer 1

A. 1.0 foot

Step-by-step explanation:

Given values

v = 8 # speed in feet per second

g = 32 # acceleration due to gravity in feet/second²

# Using the formula v = sqrt(2gh) to find h

# Rearranging the formula to solve for h: h = v² / (2g)

h = v² / (2g) = (8)² / (2*(32))

h = 64 / 64 = 1

The hammer was dropped from a height of 1 foot above the ground. ​​

Answer 2

The hammer was dropped from a height of 1 foot above the ground.

Step-by-step explanation:

To calculate the height from which the hammer was dropped, we can use the formula v=sqrt(2gh), where v is the initial speed of the hammer, g is the acceleration due to gravity, and h is the height. In this case, the initial speed of the hammer is 8 feet per second, and the acceleration due to gravity is 32 feet/second². Plugging these values into the formula, we get:

8 = sqrt(2 * 32 * h)

Simplifying, we have:

64 = 64h

Dividing both sides by 64, we find that h = 1 foot.

Therefore, the hammer was dropped from a height of 1 foot above the ground.