173k views
1 vote
If 0.09 moles of NaCl, sodium chloride, are dissolved in 3 L of water. What would be the resulting concentration?

1 Answer

7 votes

Final answer:

The resulting concentration of the NaCl solution with 0.09 moles of NaCl dissolved in 3 liters of water is 0.03 M.

Step-by-step explanation:

To determine the concentration of a sodium chloride (NaCl) solution, the molarity formula, M = moles of solute / liters of solution, is applied. Given the dissolution of 0.09 moles of NaCl in 3 liters of water, the calculation yields a molarity of 0.03 M. This signifies that there are 0.03 moles of NaCl per liter of the solution. Molarity is a crucial measure in chemistry, reflecting the amount of solute within a specific volume.

In this context, the resulting concentration of the NaCl solution, expressed as 0.03 M, elucidates the relationship between the quantity of solute and the volume of the solution, providing a standardized measure for effective comparison and analysis in chemical reactions and experiments.

User Renetta
by
9.2k points