Question

......................,.,................​

Answer 1

a=6, b=2

Explanation:

Use simplification into substitution

`(a)/(3) =1+(2)/(b)`

`a=3(1+(2)/(b))`

`a=3+(6)/(b)`

We can now plug this value of a into the second equation.

`(3+(6)/(b) )/(4) +(3)/(b) =3`

Get rid of fractions in the numerators and/or denominators

`(3b+6)/(4b) +(3)/(b) =3`

Then we can match the denominators

`(3b+6)/(4b) +(12)/(4b) =3`

Combine

`(3b+18)/(4b) =3`

Divide both sides by three

`(b+6)/(4b) =1`

Get rid of fractions

`b+6=4b`

Single out b

`6=3b`

`b=2`

Now we can plug it into the equation

`(a)/(3) -(2)/(2) =1`

`(a)/(3) =2`

`a=6`

Now we can check it;

`(6)/(3) -(2)/(2) =1`

↑CORRECT

`(6)/(4) +(3)/(2) =3`

↑CORRECT