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Store A Store B

Bread $2.20 $2.50
Milk $3.60 $3.40


Mary needs to buy bread and milk for her church picnic. At Store A, she would pay $44.20. At Store B, she would pay $44.70.


Which of the following system of equations represents this situation?
a. 2.20b+2.50m=44.20, 3.60b+3.40m=44.70
b. 220b+3.60m=44.20, 2.50b+3.40ra=44.70
c. 2.20b+2.50b=44.20, 3.60m+3.40m=44.70
d. 2.20b+3.60b=44.20, 2.50m+3.40m=44.70

1 Answer

5 votes

Final answer:

The correct system of equations that represents this situation is: 2.20b + 2.50m = 44.20 and 3.60b + 3.40m = 44.70.

Step-by-step explanation:

The correct system of equations that represents this situation is:




  1. 2.20b + 2.50m = 44.20

  2. 3.60b + 3.40m = 44.70



To determine the correct system of equations, we need to set up equations based on the prices and quantities mentioned in the problem. We use 'b' to represent the quantity of bread and 'm' to represent the quantity of milk.



For Store A:

Price of bread: $2.20, Quantity of bread: 'b'

Price of milk: $2.50, Quantity of milk: 'm'



For Store B:

Price of bread: $3.60, Quantity of bread: 'b'

Price of milk: $3.40, Quantity of milk: 'm'



Setting up the equations based on the total cost at each store:


  1. 2.20b + 2.50m = 44.20

  2. 3.60b + 3.40m = 44.70

User Kgautron
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