Final answer:
To solve for the cost of each rose bush and each bag of soil, we set up two equations based on the transactions from Friday and Saturday. By using substitution or elimination methods, we can find the price of each rose bush (R) and each soil bag (S).
Step-by-step explanation:
The question is asking us to find the cost of each rose bush and each bag of soil based on two separate transactions that include different quantities of these items. We have two equations based on the given information: 3 rose bushes (R) and 4 bags of soil (S) cost $43, and 3 rose bushes (R) and 6 bags of soil (S) cost $54.
Let R represent the cost of one rose bush and S represent the cost of one bag of soil. The equations derived from the transactions are:
- 3R + 4S = $43 (Friday's transaction)
- 3R + 6S = $54 (Saturday's transaction)
To find the individual costs of R and S, we can use methods such as substitution or elimination. For instance, we could subtract the first equation from the second to eliminate R and solve for S. Then we could use the value of S to solve for R from either of the original equations..