Question

IP Electromagnetic wave 1 has a maximum electric field of 54 V/m , and electromagnetic wave 2 has a maximum magnetic field of 2.0 μT .' Calculate the average intensity of the first wave. Express your answer using two significant figures. Part C Calculate the average intensity of the second wave. Express your answer using two significant figures.

Answer 1

The average intensity of electromagnetic wave 1 is 2.81 x 10^-16 W/m² and the average intensity of electromagnetic wave 2 is 5.96 x 10^-14 W/m².

Step-by-step explanation:

The average intensity of an electromagnetic wave can be calculated using the formula:

Iave = (1/2) * c * ε0 * Emax²,

where Iave is the average intensity, c is the speed of light (3.00 x 10^8 m/s), ε0 is the permittivity of free space (8.85 x 10^-12 F/m), and Emax is the maximum electric field strength.

For electromagnetic wave 1, the maximum electric field strength is given as 54 V/m. Plugging this value into the formula:

Iave = (1/2) * (3.00 x 10^8 m/s) * (8.85 x 10^-12 F/m) * (54 V/m)² = 2.81 x 10^-16 W/m².

For electromagnetic wave 2, the maximum magnetic field strength is given as 2.0 μT (2.0 x 10^-6 T). To find the maximum electric field strength, we can use the relationship B = E/c, where B is the magnetic field strength and c is the speed of light:

E = B * c = (2.0 x 10^-6 T) * (3.00 x 10^8 m/s) = 6.00 x 10^2 V/m.

Plugging this value into the formula:

Iave = (1/2) * (3.00 x 10^8 m/s) * (8.85 x 10^-12 F/m) * (6.00 x 10^2 V/m)² = 5.96 x 10^-14 W/m².