Final answer:
To calculate the energy of a photon with a frequency of 1.2 x 10¹⁵ Hz, use the equation E = hf, where h is Planck's constant. The resulting energy is approximately 7.95 x 10⁻¹⁹ Joules.
Step-by-step explanation:
The question asks for the energy in joules of a photon with a frequency of 1.2 x 10¹⁵ Hz. To find this, we can use the equation E = hf, where E is the energy of a photon, h is the Planck's constant (6.626 x 10⁻³⁴ J·s), and f is the frequency of the photon.
Substituting the values into the equation, we get:
E = (6.626 x 10⁻³⁴ J·s) × (1.2 x 10¹⁵ Hz) = 7.9512 x 10⁻¹⁹ J.
Therefore, the energy of the photon with a frequency of 1.2 x 10¹⁵ Hz is approximately 7.95 x 10⁻¹⁹ J.