Question

While competing in the olympics, an athlete hurls a discus with a velocity of 14 m/s at an angle of 51a box of mass 14 kg sits on an inclined surface with an angle of 52 degrees. what is the component of the weight of the box along the surface?. what is the horizontal component of the discus's velocity?

a. 12.2 m/s
b. 10.9 m/s
c. 8.8 m/s
d. 7.1 m/s

Answer 1

The component of the weight of the box along the surface is 109.04 N. The horizontal component of the discus's velocity is 8.8 m/s.

Step-by-step explanation:

To find the component of the weight of the box along the surface, we can use trigonometry. The weight of the box is given by the formula W = mg, where m is the mass of the box and g is the acceleration due to gravity. The component of the weight along the surface can be found using the formula W_parallel = W * sin(θ), where θ is the angle of the incline. So, the component of the weight of the box along the surface is:

W_parallel = 14 kg * 9.8 m/s^2 * sin(52°) = 109.04 N

To find the horizontal component of the discus's velocity, we can use trigonometry as well. The horizontal component of the velocity can be found using the formula V_horizontal = V * cos(θ), where V is the magnitude of the velocity and θ is the angle of the velocity. So, the horizontal component of the discus's velocity is:

V_horizontal = 14 m/s * cos(51°) = 8.8 m/s