Final answer:
To calculate the volume of chlorine gas at STP that is equal to 14.5 g of Cl2, you need to use the molar mass and Avogadro's number. The volume of chlorine gas at STP equal to 14.5 g of Cl2 is 4.57 L.
Step-by-step explanation:
To calculate the volume of chlorine gas at STP that is equal to 14.5 g of Cl2, we need to use the molar mass and Avogadro's number. The molar mass of chlorine gas (Cl2) is 70.90 g/mol. From the given mass of 14.5 g, we can calculate the number of moles of chlorine gas using the formula:
moles = mass / molar mass
moles = 14.5 g / 70.90 g/mol = 0.204 mol
At STP, one mole of any gas occupies a volume of 22.4 L. Therefore, the volume of chlorine gas equal to 14.5 g of Cl2 at STP is:
volume = moles * molar volume
volume = 0.204 mol * 22.4 L/mol = 4.57 L