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Using the following equations,

find g(f(x)):
f(x) = x²
g(x)=x-1
g(f(x)) = x^(?)+(?)

Using the following equations, find g(f(x)): f(x) = x² g(x)=x-1 g(f(x)) = x^(?)+(?)-example-1
User Hadi Tok
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1 Answer

5 votes

Final answer:

The function g(f(x)) = x² - 1.

Step-by-step explanation:

To find g(f(x)), we must first apply the function f to x, and then apply g to the result of f(x).

The function f(x) is given as f(x) = x² and the function g(x) is given as g(x) = x - 1.

We'll compute g(f(x)) by substituting f(x) into g(x).

Here is the step-by-step process:

Compute f(x): f(x) = x².

Substitute f(x) into g(x): g(f(x))

= g(x²) = x² - 1.

This shows that g(f(x)) = x² - 1, and therefore in the form asked for in the question g(f(x)) = x² + (?), the missing value is -1.

User Utaal
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