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35 votes
35 votes
A division problem has 56

as its divisor. The partial quotients are
10 and 8. The remainder is 2. What
the dividend?

A division problem has 56 as its divisor. The partial quotients are 10 and 8. The-example-1
User Derek Slager
by
3.2k points

2 Answers

5 votes
5 votes

Answer: 562, 450

Explanation:

When a quotient is 10, the remainder is 2.

Then the dividend: 56x10+2=562

when a quotient is 8, the remainder is 2

then the dividend; 56x8+2=450

User Q Boiler
by
2.6k points
12 votes
12 votes

Answer:

  • The dividend is 1010

Explanation:

Let the dividend is x.

The partial quotients are 10 and 8 and the remainder is 2.

  • x / 56 = 10 - first partial quotient
  • (x - 10*56) / 56 = 8 - second partial quotient and the remainder is 2.

Find the dividend:

  • x - 560 = 8*56 + 2
  • x - 560 = 450
  • x = 450 + 560
  • x = 1010
User Marutha
by
2.7k points