9.6k views
3 votes
Which of the following are vertical asymptotes of the function y = 3 cos (1/2x) - 4?

check all that apply.
a. x = π/2
b. x = 3 π
c. x = -2 π
d. x = 0

User Liker
by
8.0k points

1 Answer

4 votes

Final answer:

The vertical asymptotes of the function y = 3 cos (1/2x) - 4 are x = 0 and x = 2π.

Step-by-step explanation:

The vertical asymptotes of a function occur where the function approaches infinity or negative infinity as the input approaches a certain value. In the function y = 3 cos (1/2x) - 4, the vertical asymptotes can be found by solving for x when the cosine function equals 1 or -1.

Let's solve for x when cos (1/2x) = 1:

1 = cos (1/2x)

1/2x = 0

x = 0

So, one of the vertical asymptotes is x = 0.

Now, let's solve for x when cos (1/2x) = -1:

-1 = cos (1/2x)

1/2x = π

x = 2π

So, the other vertical asymptote is x = 2π.

User Aleksey Potapov
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories