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Tom kicks a rock horizontally off of a 20.0m high cliff. How fast did he kick the rock if it hits the ground 45.0m from the base of the cliff?

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Final answer:

To find the initial speed at which Tom kicked the rock, we can use the formulas for the horizontal and vertical motion of a projectile.

Step-by-step explanation:

To find the initial speed at which Tom kicked the rock, we can use the formula for the horizontal motion of a projectile:

d = v0x * t

Where d is the horizontal distance (45.0 m), v0x is the initial horizontal velocity (which is the speed at which the rock was kicked), and t is the time of flight.

Since the rock was kicked horizontally, the initial vertical velocity is 0 m/s, and the vertical motion can be described by the formula:

d = v0y * t + (1/2)*g*t2

Where v0y is the initial vertical velocity, which is 0 m/s, g is the acceleration due to gravity (9.8 m/s2), and t is the time of flight.

Since the rock starts at a height of 20.0 m and hits the ground, the vertical displacement can be calculated as:

20.0 m = (1/2)*g*t2

By solving this equation for t, we can find the time of flight, which will allow us to find the initial horizontal velocity v0x.

Substituting the value of t into the equation for horizontal motion, we can solve for v0x

User Vincent Jacquel
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