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The surface area S(r) in square units of a cylinder with a volume of 18 cubic units is a function of its radius r in units where S(r)=2πr² + 36/r . What is the surface area of a cylinder with a volume of 18 cubic units and a radius of 3 units?

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Final answer:

The surface area of a cylinder with a radius of 3 units and a volume of 18 cubic units is 18π + 12 square units.

Step-by-step explanation:

To find the surface area of a cylinder with a volume of 18 cubic units and a radius of 3 units, we can use the formula S(r) = 2πr² + 36/r. Plug in the values for the radius and volume: S(3) = 2π(3)² + 36/3. Calculate the values: S(3) = 2π(9) + 12. Simplify the equation: S(3) = 18π + 12. So, the surface area of the cylinder is 18π + 12 square units.

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