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The neutrons in a parallel beam, each having kinetic energy .028 eV, are directed through two slits 0.42 mm apart.How far apart will the interference peaks be on a screen 1.0 m away?

User Scytale
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Final answer:

The distance between interference peaks can be calculated using the formula for the fringe separation. Plugging in the given values, we can calculate the distance between the interference peaks as 15 mm.

Step-by-step explanation:

The distance between interference peaks can be calculated using the formula for the fringe separation:

d = λL / d

where d is the distance between the slits, L is the distance between the slits and the screen, and λ is the wavelength of the neutrons.

Plugging in the given values, we can calculate the distance between the interference peaks:

d = (.42 mm)(1.0 m)/(.028 eV)

d = 15 mm

User Rtoijala
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