Final answer:
The density of seawater is 1.025 × 10³ kg/m³, and the depth is 11 km. The pressure is found to be approximately 1093 atmospheres.
Step-by-step explanation:
The question asks us to calculate the pressure due to the ocean at the bottom of the Marianas Trench. The necessary depth of the trench is given as 11.0 km, and the density of seawater is a constant 1.025 × 10³ kg/m³. To calculate the pressure in atmospheres, we can use the formula P = ρgh, where ρ is the density of the seawater, g is the acceleration due to gravity (9.81 m/s²), and h is the depth of the water.
Calculating it out:
P = (1.025 × 10³ kg/m³) × (9.81 m/s²) × (11,000 m) = 110.72 × 10¶ Pa
Since 1 atmosphere (atm) is equivalent to 101325 Pa, we divide the pressure in Pascals by 101325 to get the pressure in atmospheres:
Pressure in atm = Pressure in Pa / 101325
Pressure in atm = 110.72 × 10¶ Pa / 101325 Pa/atm ≈ 1093 atm
This calculation shows that the pressure due to the ocean at the bottom of the Marianas Trench is approximately 1093 atmospheres, assuming a constant density of seawater.